A car moving with a velocity 54 km/hr on a straight road stops on applying brakes after covering a distance of 20 m. Compute the acceleration of the car?
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v^2=u^2+2as
(0)^2=(54)^2+2xax20
2916+40a=0
40a=-2916
a=-2916/40
a=72.9m/s
(0)^2=(54)^2+2xax20
2916+40a=0
40a=-2916
a=-2916/40
a=72.9m/s
skirfan92004:
Wrong answer
its wrong ans
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