a car moving with a velocity 90 km/h with a uniform acceleration of 5 m/s2 then find out the time require to attain a velocity double of initial velocity also find the distance covered in this time
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I understand the question as of follows; A car initially at rest increases its velocity from 0m/s to 150m/s (90km/h).Then travels the rest with the uniform acceleration.
1)Convert km/h to m/s.
2)Use acceleration= difference in velocity /time:( 300-150) /t = 5.Solve to get t = 30S.
3)Use s=ut+1/2at^2 and find the displacement.
(u=150,t=30,a=5)
1)Convert km/h to m/s.
2)Use acceleration= difference in velocity /time:( 300-150) /t = 5.Solve to get t = 30S.
3)Use s=ut+1/2at^2 and find the displacement.
(u=150,t=30,a=5)
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