A car moving with a velocity of 10 m/s. how far does it move in 45 minutes
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Explanation:
Final velocity is zero.and acceleration is −ve
0=u
2
−2×a×s
s=
2a
u
2
s∝u
2
if car moving with a velocity of 10m/s can be stopped by the application of a constant force F in a distance of 20m, since the velocity is tripled stopping distance will become 3
2
=9times.
New stopping distance =9∗20=180m
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