Question

A car moving with a velocity of 10 ms gains a velocity of 30 ms after travelling a distance of 4kn then acceleration is a) 0.1 ms? b) 0.45 ms c) 0.25 ms d) 0.35 ​

Answer 1

Answer:

option a is correct i.e 0.1 ms^-1

Explanation:

given that

initial velocity (u)=10 ms^-1

final velocity (v)=30ms^-1

total distance traveled (s)=4000m

so we have to apply equation of motion

v^2-u^2=2as

put values

(30)^2-(10)^2=2a(4000)

900-100=2a(4000)

800=a(8000)

a=800/8000

a=1/10

a=0.1