Physics, asked by radhasharma26, 6 months ago

 A car moving with a velocity of 20m/s changes to 25 m/s in 2 minutes. If the mass of the car is 1000 Kg, find the force exerted to change the velocity. ​

Answers

Answered by tusharraj77123
2

Answer:

\large\tt\color{blue}\underline{\underline{\dag{Question:}}}

\textsf{A car with a velocity of 20 m/s changes to 25 m/s}\textsf{in 2 minutes.  If the mas of the car is 1000 kg,}\textsf{find the force exerted to change the velocity.}

\large\tt\color{red}\underline{\underline{\dag{Given:}}}

\textsf{Intial velocity of the car = 20 m/s}

\textsf{Final velocity of the car = 25 m/s}

\textsf{Time taken to change the velocity = 2 mins}

\textsf{Mass of the car = 1000 kg}

\large\tt\color{orange}\underline{\underline{\dag{To\:find:}}}

\textsf{Force exerted to change the velocity}

\large\tt\color{Brown}\underline{\underline{\dag{Concept:}}}

\textsf{▪︎First , find the acceleration of the car.}

\textsf{▪︎Then make m/min to m/sec.}

\textsf{▪︎Then find the force exerted}

\large\tt\color{pink}\underline{\underline{\dag{Taken:}}}

\bold\green{A=\frac{V-V1}{T}}

\bold{Where,}

\bold{A=Acceleration}

\bold{V=Final\:velocity}

\bold{V1=Initial\:velocity}

\bold{T=Time\:taken}

\bold\green{In\:m/s=\frac{m/min}{60}}

\bold{Where,}

\bold{m/s=Acceleration\:in\:meter\:second}

\bold{m/min=Acceleration\:in\:meter\:minute}

\bold\green{F=MA}

\bold{Where,}

\bold{F=Force\:exerted\:by\:the\:car}

\bold{M=Mass\:of\:the\:car}

\bold{A=Acceleration\:in\:meter\:second}

\large\tt\color{cyan}\underline{\underline{\dag{Solution:}}}

\bold\green{Taken,A=\frac{V-V1}{T}}

\bold\mapsto{A=\frac{25m/s-20m/s}{2min}}

\bold\mapsto{A=\frac{5m/s}{2min}}

\bold\mapsto{A=2.5\:m/min}

_____________________________

\bold\green{Now,convert\:m/min\:into\:m/sec}

\bold\green{Taken,In\:m/s=\frac{m/min}{60}}

\bold\mapsto{In\:m/s=\frac{2.5}{60}}

\bold\mapsto{In\:m/s=0.0416m/s(approx)}

_____________________________

\bold\green{At\:last\:find\:the\:force}

\bold\green{F=MA}

\bold\mapsto{F=1000kg×0.0416m/s}

\bold{\boxed{\purple{F=41.6N}}}

So , the force exerted to change the velocity is 41.6 N.

_____________________________

\large\tt\color{magenta}\underline{\underline{\dag{Extra\:information:}}}

\bold{• Velocity=\frac{Displacment}{Time}}

\bold{• Average\:speed=\frac{Total\:distance}{Total\:time\:taken}}

\bold{• Speed=\frac{Distance}{Time}}

HOPE IT HELPS YOU

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