a car moving with a velocity of 30 MS - 1 is taught by the application of break switch in part retardation of 6 m s -2 to the car.
1) how long does it take for car to come to a stop?
2) how far does the car travel during the time brakes are applied?
Answers
Answered by
2
1> the car takes 5 seconds to rest
2>the distance covered is 75 mtrs
2>the distance covered is 75 mtrs
Answered by
2
Given,
U=30
V=0
a=-6
So,v=u+at
0=30+(-6×t)
Time =5sec
Distance =75m (s=ut+1/2at^2)
U=30
V=0
a=-6
So,v=u+at
0=30+(-6×t)
Time =5sec
Distance =75m (s=ut+1/2at^2)
lakhipriyadas1:
Thnx for choosing my answer as brainliest
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