A car moving with a velocity of 36 km / hr is brought to rest in 5 second by applying broken find the retardation applying on it
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Answered by
2
Answer:
put the diatance formula and solve it mate
Answered by
10
Explanation:
Given ;u=36km/hr=36×(5/18)=10m/s
and t=5sec
use newtons eqn if motion
v=u+at
here v=0; as car is stopped
so 0=10+a×5
5a= -10
a= -2m/s2
hope it helped .
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