Question

A CAR MOVING WITH A VELOCITY OF 72KMPH STOPS ENGINE JUST BEFORE ASCENDING AN INCLINED ROAD. IF 25% OF ENERGY IS WASTED IN OVERCOMING FRICTION , THE CAR RISES TO A HEIGHT OF

Answer 1

KE just before approaching the inclined plane ..50m

25%of it ..50m/4

therefore PE=KE....................(1)

let the hieghtt be h

PE..mgh

using eq1

mgh=50m/4

h=50/4g

5/4=1.25m

Answer 2

Answer:

KE just before approaching the inclined plane ..50m

25%of it ..50m/4

therefore PE=KE....................(1)

let the hieghtt be h

PE..mgh

using eq1

mgh=50m/4

h=50/4g

5/4=1.25m