Question

A car moving with an initial velocity of 36km/hr is brought to rest in 5s,calculate the retardation produced​

Answer 1

Answer:

u=36 km/hr

=5/18*36

=10 m/s

v=0

t=5 s

a=(v-u)/t

=(0-10)/5

=-10/5

=-2 m/s^2

S=ut+1/2at^2

=10*5+1/2*-2*5*5

=50-25

=25 m

Therefore retardation is 2 m/s^2 and the distance covered by the car before coming to rest is 25 m.

Answer 2

Answer:

the retardation produced id 36km/h

as redardation means negative acceleration...

but here the negative acceleration is - 36km/h but we will write 36km/h as the word retardatin itself means negative acceleration.. so go through

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