Question

A car moving with an intial of 60m/s is brought to rest in 30s calculate the acceleration ​

Answer 1

Answer:

apply v=u+at

u=60 given and since it is brought to rest so v=0 i.e final velocity

put the values in the equation

0=60+(a*30)

so solving thus we will get a=-2m/s^2

mark brainlist if understood

Answer 2

20m/sec

Explanation:

$a = \frac{v - u}{t} = \frac{60 - 0}{30} = \frac{60}{30} = 20$