a car moving with constant acceleration cover the distance between two point in 6 second. it's speed when it's passes the second point is 15m/sec. what Will be its velocity when it's pass from first point,if the distance between the two points is 60metre.
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After 6s, it is given that final velocity is 15 m/s
Therefore,
15 = u + 6a
2 × a × 60 = 15^2 - u ^2
120a = u^2 + 36a^2 + 12au - u^2
120a = 36a^2 + 12au
120 = 36a + 12u
10 = 3a + u
15 = u + 3a + 3a
15 = 10 + 3a
a = 5/3 m/s^2
Using this, we get u = 5m/s
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