A car moving with constant acceleration covers the distance between two points 180 m apart in
6 sec. Its speed as it passes the second point is 45 m/s. What is its acceleration and its speed at the
first point
1) -5 m/s2, 15 m/s 2) -15 m/s2, 5 m/s 3) -5 m/s2; -15 m/s 4) 5 m/s2; 15 m/s
Answers
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Answer:
4) 5 m/s2; 15 m/s
Explanation:
V=45 m/s
u=?
a=?
S=180m
T=6 s
We know that
V=u + at
45=u+6a. . Equation 1
By second equation of motion
S=ut +1/2at^2
180=6u +18a equation 2
Solving one and 2 we get
U=15
A=5
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