A car moving with constant acceleration crosses two points a and b with velocities 10 mps and 20 mps in its path . find the velocity of the car midway between a and b
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Initial speed= u=20m/sfinal speed=v=30m/sa=acceleration=a m/s²distance be = s mFrom third equation of motion :V²-u²=2asCase i)30²-20²=2as900-400=2as2as=500case 2) Mid point:v²-u²=2as/2v²-400=500/2v²=400+250v=√650v=25.49 m/s≈25.5 m/s∴ The velocity of the car midway between a and b is 25.5 m/s
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