Question

a car moving with constant speed 90 kmh the driver switched off the engine the car stops after 20 secs find
acceleration of the car
distance traveled by the car
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Answer 1

Initial velocity u = 90 km/hr * 5/18

= 25 m/s

Final velocity v = 0 m/s

Time T = 20 s

Acceleration = (v-u)/T

= (0-25)/20

= -25/20

= -5/4

= -1.25 ms-2

Distance = ut + 1/2 at2

= 25*20 + 1/2* (-1.25)*20*20

= 500 + (-1.25)*200

= 500 + (-250)

= 500 - 250

= 250 m

Hope it helps

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Answer 2

Thank you so much ʕ•ᴥ•ʔ