Question

a car moving with initial velocity 50 metre per second uniform retardation with the rate of 5 metre per second square find the distance covered by a car before coming to rest and also find the time taken by it​

Answer 1

Explanation:

v=0 , u=50 , a=-5 so by eqn,

v square - u square = 2ax

we got distance x = 250 .

and by eqn,

v=u +at we can get time also..