Question

a car moving with initial velocity of 10 ms -1 ,accelerates at a rate of 2 m s-2. its velocity will become 15 m s -1 in
(a)1s
(b)2.2s
(c)2.5s
(d)5s
​

Answer 1

Gɪᴠᴇɴ :-

• Initial velocity (u) = 10 m/s
• Final velocity (v) = 15 m/s
• Acceleration (a) = 2 m/s²

ᴛᴏ ғɪɴᴅ :-

• Time taken (t)

sᴏʟᴜᴛɪᴏɴ :-

On using 1st equation of motion, we get,

➨ v = u + at

➨ 15 = 10 + 2 × t

➨ 15 - 10 = 2t

➨ 2t = 5

➨ t = 5/2

➨ t = 2.5 s

Hence,

• Time taken is 2.5 seconds

Therefore,

• Option (c) 2.5 s is correct option

Answer 2

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Option.D

Explanation:-

Given,

➡️Initial velocity = 10m/s (u)

➡️Final velocity = 15m/s (v)

➡️Acceleration = 2m/s^2 (a)

We know that,

Kinetic equation = (V=u+at)

V=u+at

15=10+2×t

2t = 15-10

2t = 5

$t = \frac{5}{2}$

$\huge{2.5 s}$

Hence , The answer is Option.D