Question

A car moving with of 50km/hr can be stooped by brakes after at least 6m. if the same car is moving at speed of 100km/hr the minimum stopping distance is.

Answer 1

HEY DEAR HERE IS YOUR ANSWER ✌✌❤❤

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GIVEN - Initial velocity, ( u ) = 50 km/h = 50 × (5/18) = 250/18 m/s

Final velocity, ( v ) = 0

Distance travelled before coming to rest, s = 6 m

Using, v2 = u2 + 2as

=> a = -u2/(2s)

=> a = -16.075 m/s2

Again,

u = 100 km/h = 500/18 m/s

v = 0

a = -16.075 m/s2

Now, v2 = u2 + 2as

=> s = -u2/(2a) = 24 m

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HOPE IT HELPS YOU.✌✌
THANKS.❤❤

Answer 2

ANSWER:-
=>Initial velocity, u = 50 km/h = 50 × (5/18) = 250/18 m/s

=>Final velocity, v = 0

=>Distance covered by the car before coming to rest, s = 6 m

=>Using, v^2 = u^2 + 2as

=> a = -u^2/(2s)

=> a = -16.075 m/s^2
So,
u = 100 km/h = 500/18 m/s
v = 0
a = -16.075 m/s^2
Now, v^2 = u^2 + 2as

=> s = -u^2/(2a) = 24 m