A car moving with speed 108km/h is stopped in 5 sec .find the force applied by the breaks and distance covered by the car before it stops
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Explanation:
given: u = 108 km/hr => 108 × 5/18 = 30 m/sec
v = 0, t = 5 sec
to find: force applied on tne brake
distance covered before coming to rest
v = u + at
=> 0 = 30 + a×5
=> 5a = -30
=> a = -30/5 => - 6 m/sec²
therefore retardation = - 6m/sec²
s = ut + 1/2 a t²
s = 30×5 + 1/2(-6)5²
s = 150 - 3*25
s = 150 - 75 => 75 m
car travels 75 m before coming to a stop
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