A car moving with speed 30 m/s on a circular path
of radius 500 m. Its speed is increasing at the rate
of 2m/s2. The acceleration of the car is :-
Answers
Answer:
2.7 m/s²
Explanation:
Speed of the car = 30 m/s
circular path of radius 500 m
Its speed is increasing at the rate of 2m/s2.
Acceleration = ?
=> Total acceleration is equal to the root of the squared sum of centripetal acceleration and tangential acceleration.
Thus, centripetal acceleration, a_n = v²/ radius = 30²/500
Tangential acceleration, a_t = 2 m/s²
=> Total acceleration:
a_total = √ a_t² + a_n²
= √2² + (30²/500)²
= √2² + 1.8²
= √4 + 3.24
= √7.24
= 2.7 m/s²
Answer:
2.7 m/s²
Explanation:
=> It is given that,
Speed of a car = 30m/s
Radius of circular track = 500m.
Its speed is increasing at the rate of 2m/s2.
Acceleration = ?
=> Total acceleration is equal to the root of the squared sum of centripetal acceleration and tangential acceleration.
Thus, centripetal acceleration, a_n = v²/ radius = 30²/500
Tangential acceleration, a_t = 2 m/s²
=> Total acceleration:
a_total = √ a_t² + a_n²
= √2² + (30²/500)²
= √2² + 1.8²
= √4 + 3.24
= √7.24
= 2.7 m/s²
Thus, the value of the acceleration of a car is 2.7 m/s².