Question

A car moving with speed of 20m's applies the breaks and comes to rest after travelling 10 m. Calculate the fore applied by the breakes of car. Given mass of is 200 kg that car​

Answer 1

Answer:

F=-4000N

Explanation:

v^2=u^2+2aS

0=400+2a*10

-40=2a

a=-20m/s^2

F=ma

F=-20*200

F=  -4000N

PLEASE MARK BRAINIEST

Answer 2

Hi mate

Here is your answer

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u= 20 m/s

v=0m/s

s=10m

m= 200 kg

v^2 - u^2 =2as

0 - 20^2 = 2a * 10

-400/20= a

a=-20m/s^2

F = m * a

= 200 * -20

= -4000N

So , the force applied is -4000N

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