A car moving with speed v on a straight track can
be stopped in a distance x by applying brakes. If
same car is moving with speed 2v and brakes
provide half the retardation then car will stop after
travelling distance
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Answer:
8d
Explanation:
Assume retardation is a
initial velocity = v
final velocity = 0
by using formula, v^2=u^2+2as
0=v^2+2ad
v^2=2ad
a=v^2/2d
so retardation in second case
a'=a/2
a'=v^2/4d
Now, use S=u^2/2a'
put value of a'
Here, u=2v
S=(2V)^2/2*V^2/4d
S=2*4d
S=8d
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