a car moving with the acceleration 2m/s/s.find the distance travelled by the car in 10 th second
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2
Answer:
Answer:
Explanation:
From the Question,
Given :-
Initial Velocity (u) = 0m/s
Acceleration (a) = 2 m/s²
To find :-
Distance travelled in the 10th second (n = 10s)
Distance travelled in nth second is given by :
\boxed{\boxed{\sf s_n = u + \dfrac{a}{2}(2n - 1)}}
s
n
=u+
2
a
(2n−1)
Putting n = 10s,
\begin{lgathered}\longrightarrow \sf s_{10} = 0 + \dfrac{2}{2}([2(10) - 1] \\ \\ \longrightarrow \sf s_{10} = 20 - 1 \\ \\ \huge{\longrightarrow \sf s = 19 \ m}\end{lgathered}
⟶s
10
=0+
2
2
([2(10)−1]
⟶s
10
=20−1
⟶s=19 m
Thus, the distance travelled in the 10th second is 19 m.
Explanation:
BTS ARMY
Answered by
0
Answer:
Thus, the distance travelled in the 10th second is 19 m.
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