a car moving with the initial 15 m/s car stopped after 5 s by application of breaks.find the retardation
Answers
Answered by
2
Answer:
-3
Explanation:
v=u+at
0=15+5a
a=-15/5
a=-3
i hope it is helpful..
Answered by
20
Given :
Initial velocity = 15m/s
time taken = 5sec
Final velocity = zero
To find :
The retardation of car.
Solution :
As we are provided with initial velocity, final velocity and time we can use first equation of kenimatics that is,
v = u + at
where,
- v denotes final velocity
- u denotes initial velocity
- a denotes acceleration
- t denotes time
substituting all the given values in the equation,
➠ v = u + at
➠ 0 = 15 + (a)(5)
➠ -15 = 5a
➠ a = -15/5
➠ a = -3m/s²
If the speed is decreasing with time then accerlation is negative. The negative accerlation is called deceleration or retardation.
➠ Retardation = -a
➠ Retardation = -(-3)
➠ Retardation = 3m/s²
thus, retardation of car is 3m/s².
Remember !
SI unit of accerlation is metre per second square (m/s²).
Similar questions