A car moving with the speed of72 km per hour is brought to rest in 10 sec by applying brakes find the acceleration and distance
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the initial velocity being is a straight line, and the final velocity being 0 km/hr, or o m/s, then:
v(final) = v(initial) + at
0 = 72 Km/h + (-=a * 10 s)
- a * 10 s = 72 km/hr * hr/3600s * 1000m/km = 20m/s
a = - (20 m/s) / (10 s)
a = - 2 m/s^2
By retardation I think you mean negative acceleration or deceleration. That’s 2 m/s^2.
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