Question

A car moving with the velocity of 54km/hrs accelerate uniformly at the rate of 2m/s,calculate the distance traveled from the place where the acceleration began to where the velocity reach 72km/hrs and the time taken to covered the distance ​

Answer 1

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Answer 2

$\huge\boxed{\red{Question}}$

A car moving with the velocity of 54km/hrs accelerate uniformly at the rate of 2m/s,calculate the distance traveled from the place where the acceleration began to where the velocity reach 72km/hrs and the time taken to covered the distance.

$\huge{\boxed{\red{Solution}}}$

Given,

We know that

• Car is moving with a velocity of 54km/h at it accelerates at 2m/s².
• The final velocity of the car is 72km/h.

We have to find,

• The distance travelled by the car and time taken by the car.

Now,

Converted km/h to m/s.

u = 54 km/h = 15 m/s

v = 72 km/h = 20 m/s

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u = 15 m/s ; v = 20 km/h ; a = 2m/s² ; s = ? ; t = ?

We have to use first equation of motion to find time.

➣ v = u + at

➣ 20 = 15 + 2t

➣ 20 - 15 = 2t

➣ t = 5/2

➣ t = 2.5sec

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We have to use third equation of motion to find distance.

➣ s = ut + 1/2 at²

➣ s = 15(2.5) + 1/2 × 2 × 2.5 × 2.5

➣ s = 37.5 + 6.25

➣ s = 43.75m

✐ Hence the distance travelled by the car is 43.75m