A car moving with uniform acceleration attains speed of 36km/hr in 2 minutes find the acceleration
Answers
✬ Acceleration = 0.083 m/s² ✬
Explanation:
Given:
- Initial velocity of car is 0.
- Final velocity of car is 36 km/h.
- Time taken to attain final speed is 2 minutes.
To Find:
- What is the acceleration of car ?
Formula to be used:
- v = u + at
Solution: First change the final velocity from km/h to m/s and also time to seconds.
[ To change km/h to m/s multiply by 5/18 ]
➙ Final velocity = 36(5/18) = 10 m/s.
[ 1 minutes = 60 seconds ]
➙ 2 minutes = 2(60) = 120 seconds.
Now, we have
- v = 10 m/s.
- u = 0 m/s.
- t = 120 s.
v = u + at
10 = 0 + a(120)
10 = 120a
10/120 = a
0.083 m/s² = a
Hence, the acceleration of car is 0.083 m/s².
__________________
➟ The rate of change of velocity is called acceleration. It is denoted by a.
➟ The velocity at which motion starts is termed as initial velocity. It is denote by u.
➟ The last velocity of an object after a period of time. It is denoted by v.
Given :-
- Initial velocity of car = 0.
- Final velocity of car = 36 km/h.
- Time taken to attain final speed = 2 minutes.
To Find :-
- Acceleration of car
Formula :-
- v = u + at
Where,
- v = Final Velocity
- u = Initial Velocity
- a = Acceleration
- t = Time taken
Solution :-
First of all we change the final velocity from km/h to m/s and also time to seconds.
→ Final velocity = 36(5/18) = 10 m/s.
[ We know { 1 minute = 60 seconds } ]
→ 2 minutes = 2(60) = 120 seconds.
Now, we have
- v = 10 m/s.
- u = 0 m/s.
- t = 120 s.
Put the values,
10 = 0 + a(120)
=> 10 = 120a
=> - 120a = - 10
=> a = - 10/- 120
=> a = 0.083 m/s²
Hence, the acceleration of car is 0.083 m/s².