a car moving with uniform acceleration changes its volume from 36km/h to 108 km/h .in 15 sec find acceleration and distance travelled by car during this period
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A car moving with uniform acceleration changes its volume from 36 km/h to 108 km/h .in 15 sec find acceleration and distance traveled by car during this period ?
To solve this problem let us write the given data 1st
GIVEN:
Time (t) = 15 sec
Initial Velocity (u) = 36 km/h
Final Velocity (v) = 108 km/hr
HINT:
In the question it is given that it is moving with uniform acceleration { means acceleration remains constant}
Also we need to convert speed from km/hr in terms of m/s
TO FIND:
[A] Acceleration of the car
[B] Distance traveled by the car
SOLUTION:
➠ v = u + at
Initial and final velocity should be converted in terms of m/s to do that we need to multiply given km/hr with
u = 36 km/h =
v = 108 km/h =
t = 15 sec
Let us substitute in the formula
➠ 30 = 10 + a(15)
➠ 30 = 10 + 15 a
➠
➠
➠ a = 0.2 m/s
Hence car would have traveled 0.2 m/s with its uniform acceleration
S = ?
➠ v² = u² + 2as
➠ v² - u² = 2as
➠ = S
➠
➠
➠
➠
➠ S = 2000m
Hence car would have traveled distance of 2000m with this speed
❆ Use the newtons 3 laws of motion according to given quantities and find the answers . They are,
❆ v = u + at
❆ s = ut + 1/2 at²
❆ v² - u² = 2as
❆ Sn = u + (2n -1) used to find time in nth seconds
❆ In case when distance and time are given use
❆ Speed = Distance / Time ❆
❆ With these formulas you can apply the given quantities and find the answers.
ℌope ℑt ℌelps
Thanks for asking:)
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