Physics, asked by ishimalhotra29, 4 months ago

a car moving with uniform acceleration changes its volume from 36km/h to 108 km/h .in 15 sec find acceleration and distance travelled by car during this period​

Answers

Answered by BrainlyLegend2108
9

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A car moving with uniform acceleration changes its volume from 36 km/h to 108 km/h .in 15 sec find acceleration and distance traveled by car during this period​ ?

\huge \fbox{ \underline \blue{Answer }}

To solve this problem let us write the given data 1st

GIVEN:

Time (t) = 15 sec

Initial Velocity (u) = 36 km/h

Final Velocity (v) = 108 km/hr

HINT:

In the question it is given that it is moving with uniform acceleration { means acceleration remains constant}

Also we need to convert speed from km/hr in terms of m/s

TO FIND:

[A]  Acceleration of the car

[B]  Distance traveled by the car

SOLUTION:

\pink{ \boxed{[A] \: Acceleration\: of\: the\: car  }}

➠ v = u + at

Initial and final velocity should be converted in terms of m/s to do that we need to multiply given km/hr with \dfrac{5}{18}

u = 36 km/h = \bcancel36*\dfrac{5}{\bcancel18}\ = 2\times 5 = 10\: m/s

v = 108 km/h = \bcancel108*\dfrac{5}{\bcancel18} \ = 6 \times 5 \ = 30 \ m/s

t  = 15 sec

Let us substitute in the formula

➠ 30 = 10 + a(15)

➠ 30 = 10 + 15 a

➠  \dfrac{3\cancel 0 }{1\cancel 0} = 15 a

 \dfrac{3}{15}  = a

➠ a = 0.2 m/s

Hence car would have traveled 0.2 m/s with its uniform acceleration

\pink{ \boxed{[B] \: Distance \: traveled \:by \: the\: car  }}

S = ?

➠ v² = u² + 2as

➠  v² - u² = 2as

➠  \dfrac{v² - u²}{2a} = S

➠  \dfrac{30^{2} - 10^{2}}{2\times0.2 }  = S

\dfrac{900 -100}{0.4}  = S

\dfrac{800}{0.4}  = S

\dfrac{8000}{4}  =S

➠ S = 2000m

Hence car would have traveled distance of 2000m with this speed

\underline{\underline{ \sf \huge \red{✪Extra Bytes✪}}}

❆ Use the newtons 3 laws of motion according to given quantities and find the answers . They are,

❆ v = u + at  

❆ s = ut + 1/2 at²

❆ v² - u² = 2as

❆ Sn = u +  (2n -1) used to find time in nth seconds

❆ In case when distance and time are given use

❆ Speed = Distance / Time ❆

❆ With these formulas you can apply the given quantities and find the answers.

ℌope ℑt ℌelps

Thanks for asking:)

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