Question

A car moving with uniform acceleration covers 450m in a 5 second interval and covers 700m in the next 5 second interval. The acceleration of the car is *

Answer 1

u=450
v=700 v-u/s=700-450/5=50m/s^2

Answer 2

Answer:

Acceleration, a = 10 m/s²

Explanation:

It is given that, A car moving with uniform acceleration covers 450 m in a 5 second interval. So, s = 450 m and t = 5 s

Using second equation of motion. We get,

$s=ut+\dfrac{1}{2}at^2$

$450=u(5)+\dfrac{1}{2}a(5)^2$.............(1)

Then, it covers 700 m in the next 5 second interval. So, s = 700 + 450 m = 1150 m and t = 10 s

Again, using second equation of motion we get

$s=ut+\dfrac{1}{2}at^2$

$1150=u(10)+\dfrac{1}{2}a(10)^2$................(2)

Solving equation (1) and (2).

a = 10 m/s²

So, the acceleration of the car is a = 10 m/s². Hence, this is the required solution.