Question

A car moving with uniform acceleration
describes 65m in 5th second and 105m in the
9th second. Calculate the initial velocity and
acceleration of the car.​

Answer 1

Answer:

Hope it's helpful

Explanation:

1

3

An object in uniform accelerated motion covers 65 m in 5 seconds and reaches 105 m in the 9th second. How much distance will it have covered in the 20th second? Also, calculate the distance traveled in 20 seconds.

John Falvey

Answered August 13, 2017

ut+[1/2]at^2=s , find 2 equations to solve for a and u .

t=5

5u +[1/2]a[5^2]=65 , multiply by [2/5]

2u +5a=13 , multiply by 9

18u + 45a = 117 , Eq 1

t=9

9u +[1/2]a9^2=105 , multiply by [2]

18u + 81a =210 , Eq 2

18u + 45a=117 , subtract Eq 1

36a=93 , a = 31/12

2u +5a = 13 , a = 31/12

24u/12 +155/12 =156/12

24u =1 , u =[1/24]

s0 [u,a] = [ 1/24 , 31/12]

s = ut +[1/2] at^2 , LET T =20 then

s = 20/24 + [1/2][31/12][20^2]

s =[1/24][20 +31(20^2)

s =517.5 m