A car of 900 kg running with a velocity of 72 km his stopped at a distance of 300m. Find thebraking force.
Answers
Force = Mass x Acceleration
Mass = M = 900 Kg
Acceleration = a = ??
V² = U² + 2ad
note that :
V = Final velocity = 0 m/s ( because the car stopped )
U = Intial velocity = 73 Km/hr = 20 m/s
d = Distance = 300 m
a = acceleration = ??
0² = (20)² + 2a(300)
600a = -400
a = - 4/6 = - 0.6 m/s²
Force = 900 x - 0.6 = - 600 N
Magnitude of the force = 600 N
Answer:
Force = Mass x Acceleration
Mass = M = 900 Kg
Acceleration = a = ??
V² = U² + 2ad
note that :
V = Final velocity = 0 m/s ( because the car stopped )
U = Intial velocity = 73 Km/hr = 20 m/s
d = Distance = 300 m
a = acceleration = ??
0² = (20)² + 2a(300)
600a = -400
a = - 4/6 = - 0.6 m/s²
Force = 900 x - 0.6 = - 600 N
Magnitude of the force = 600 N
Explanation: