Question

A car of 900 kg running with a velocity of 72 km his stopped at a distance of 300m. Find thebraking force.

Answer 1

Force = Mass x Acceleration  

Mass = M = 900 Kg  

Acceleration = a = ??  

V² = U² + 2ad  

note that :  

V = Final velocity = 0 m/s ( because the car stopped )  

U = Intial velocity = 73 Km/hr = 20 m/s  

d = Distance = 300 m  

a = acceleration = ??  

0² = (20)² + 2a(300)  

600a = -400  

a = - 4/6 = - 0.6 m/s²  

Force = 900 x - 0.6 = - 600 N  

Magnitude of the force = 600 N

Answer 2

Answer:

Force = Mass x Acceleration  

Mass = M = 900 Kg  

Acceleration = a = ??  

V² = U² + 2ad  

note that :  

V = Final velocity = 0 m/s ( because the car stopped )  

U = Intial velocity = 73 Km/hr = 20 m/s  

d = Distance = 300 m  

a = acceleration = ??  

0² = (20)² + 2a(300)  

600a = -400  

a = - 4/6 = - 0.6 m/s²  

Force = 900 x - 0.6 = - 600 N  

Magnitude of the force = 600 N

Explanation: