Question

A car of mas 400 kg is moving with speed 72 ms^-1, calculate the braking force that can stop the car in 10m.​

Answer 1

Answer:

HEY THERE !

m=400 kg

u=72ms^-1

v=0 since the car stops

S=10m

by using the equation

2aS=v^2-u^2

then a=v^2-u^2/2S

we will get a=-3.6ms^-2

NOW WE KNOW THAT F=ma

so force required to stop the car is 1440N

Answer 2

Answer:

103680N Newtons of force is required to stop the car in 10 meter (and if in the question 10 m is 10 minutes then 48 N is required to stop the car in 10 minutes)

Explanation:

v^2-u^2=2as

a=v^-u^2/2s

a=0-72^2/20

a=-5184/20=259.2ms-2

Force =mass ×acceleration =400×259.2=103680N

(I had a doubt that in question 10 m means 10 minutes so i want to solve it

T=10 minutes = 600 seconds

U=72 and v =0

a=v-u/t= 0-72/600= - 72/600 =0.12 ms-2

Force =mass ×acceleration

=400×0.12

=48 N)

{Next time plz give a clear question}