Question

. A car of mass 1000 kg develops a force of 500 N over a distance of 49 m. If initially the car is at rest find

final velocity and time for which it accelerates.​

Answer 1

Answer:

Solution: Force, F= 500 N ; mass of the body, m= 1000 kg.

From newtons second law of motion,

F = ma, where F, m and a are the force , mass and acceleration respectively.

a=

m

F

=

1000

500

=0.5ms

−2

To find initial velocity , consider the equation of motion v

2

=u

2

+2 as

Since the body is retarding a=−0×5ms

−2

and since it comes to rest v =0

∴0=u

2

+(2×(−0×5)×64)

0=u

2

−(1×64)⇒u

2

=64

⇒u=

64

=8ms

−1

Tofindthetimetaken,considertheequationofmotionv=u+at

0=8−0×5×t⇒t=

0.5

8

=16s

∴u= 8 ms

−1

, t=16sanda=−0×5ms

−2

Answer 2

$\huge\green{A}\orange{N}\red{S}\pink{W}{E}\blue{R}$

m=1000kg

u=0      (initially at rest)

s= 49m

F= 500N

v=?

t=?

F=ma

500= 1000a

a=0.5m/s²

v²=u²+2as

v²=2as         (u=0)

v²=2(0.5)(49)

v²=49

v= 7 m/s

a=(v-u)/t

0.5=(7-0)/t

0.5t=7

t= 14s

FOLLOW AND MARK AS BRAINLIEST