Question

a car of mass 1000 kg is moving with a certain velocity . a constant force of 1600N acts on it for 5 seconds and the velocity of the car becomes double of its initial value.. calculate the initial and final velocity of the car

Answer 1

Answer:

Given : m=1000 kg u=10 m/s t=10 s

Applied force F=1000 N (forwards)

Retarding force f=500 N (backwards)

Acceleration of the car in forward direction a=

m

F−f

=

1000

1000−500

=0.5 m/s

2

Using v=u+at

∴ v=10+0.5×10=15 m/s