a car of mass 1000 kg is moving with a speed of 36km/hr on a road calculate retarding force required to stop the car in a distance of 50 m
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Answered by
52
M=1000kg
V=36km/hr=10m/s
Dist=50m
Time=dist/velocity =5sec
acceleration, a=v/t=10/5=2m/sec^2
Force=mass×acceleration
=1000×2=2000N and..
V=36km/hr=10m/s
Dist=50m
Time=dist/velocity =5sec
acceleration, a=v/t=10/5=2m/sec^2
Force=mass×acceleration
=1000×2=2000N and..
JAYASufprince:
Mark it as brainlist ans
Answered by
59
Hey there,
◆ Answer-
F = -1000 N
◆ Explanation-
# Given-
m = 1000 kg
u = 36 km/hr = 10 m/s
v = 0
s = 50 m
# Solution-
Using Newton's 3rd kinematic eqn,
v^2 = u^2 + 2as
0 = 10^2 + 2×a×50
a = -100/100
a = -1 m/s^2
Retarding force is calculated by-
F = -ma
F = -1000 × 1
F = -1000 N
Therefore, retarding force is 1000 N in magnitude.
Hope this helps...
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