Question

A car of mass 1000 kg is moving with the initial velocity of 20m/s and a force F is applied for .001 second and it velocity is increased to 100 m/s. Calculate change in momentum and force F

Answer 1

Answer:

Initial velocity(u)=20ms

−1

Final velocity(v)=0

Distance moved(S)=50m

We know,

v

2

=u

2

+2aS

0=20

2

+2a×50

−400=100a

a=

100

−400

a=−4ms

−2

Now,

F=ma

F=1000×−4

=−4000N

Answer 2

change in momentum /acceleration=100-20/0.001 m/s²=80/0.001 m/s²=80×10³/1 m/s²=80000 m/s²

Force =ma=1000×80000 N =80000000 N