A car of mass 1000 kg moving with a speed 18 km/hr. on a horizontal surface,the coefficient of friction is 0.5 and the car colliding with a horizontal mounted spring.the spring constant is 6.25×10^3 Nm^-1.
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Answer:
Here,
m=1000 kg,v=18 km h
−1
=18×
18
5
ms
−1
=5 ms
−1
k=6.25×10
3
N m
−1
At maximum compression x
m
, the kinetic energy of the car is converted entirely into the potential energy of the spring.
∴
2
1
mv
2
=
2
1
kx
m
2
or x
m
=
k
m
v
Substituting the given values, we get
x
m
=
6.25×10
2
N m
−1
1000 kg
×5 ms
−1
=0.4×5 m=2 m.
Explanation:
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