Question

A car of mass 1000 kg moving with a velocity of 54 km/h hits a wall and comes to rest
in 5 seconds. Find the force exerted by the car on the wall.

Answer 1

Answer:

–3000 N

Explanation:

As per the provided information in the the given question, we have:

• Mass of the car (m) = 1000 kg
• Initial velocity of the car (u) = 54 km/h
• Final velocity (v) = 0 m/s [Comes to rest]
• Time taken (t) = 5 seconds

Converting initial velocity to m/s :

Multiply if by 5/18.

→ u = 54 km/h

→ u = (54 × 5/18) m/s

→ u = (3 × 5) m/s

→ u = 15 m/s

━━━━━━━━━━━━━━━━━━━━━━━━━

To calculate the force exerted by the car, we also need to calculate the acceleration.

Finding the acceleration :

By using the first equation of motion,

→ v = u + at

• v denotes final velocity
• u denotes initial velocity
• a denotes acceleration
• t denotes time

→ 0 = 15 + 5a

→ 0 - 15 = 5a

→ -15 = 5a

→ -15 ÷ 5 = a

→ - 3 m/s² = a

━━━━━━━━━━━━━━━━━━━━━━━━━

Finding the force exerted:

→ F = ma

• F denotes force
• m denotes mass
• a denotes acceleration

→ F = 1000 × (-3) N

→ F = –3000 N

∴ The force exerted by the car on the wall 3000 N, negative sign denotes that it is acting in the opposite direction.

Answer 2

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