A car of mass 1000 kg moving with a velocity of 54 km/h hits a wall and comes to rest
in 5 seconds. Find the force exerted by the car on the wall.
Answers
Answer:
–3000 N
Explanation:
As per the provided information in the the given question, we have:
Mass of the car (m) = 1000 kg
Initial velocity of the car (u) = 54 km/h
Final velocity (v) = 0 m/s [Comes to rest]
Time taken (t) = 5 seconds
Converting initial velocity to m/s :
Multiply if by 5/18.
→ u = 54 km/h
→ u = (54 × 5/18) m/s
→ u = (3 × 5) m/s
→ u = 15 m/s
━━━━━━━━━━━━━━━━━━━━━━━━━
To calculate the force exerted by the car, we also need to calculate the acceleration.
Finding the acceleration :
By using the first equation of motion,
→ v = u + at
v denotes final velocity
u denotes initial velocity
a denotes acceleration
t denotes time
→ 0 = 15 + 5a
→ 0 - 15 = 5a
→ -15 = 5a
→ -15 ÷ 5 = a
→ - 3 m/s² = a
━━━━━━━━━━━━━━━━━━━━━━━━━
Finding the force exerted:
→ F = ma
F denotes force
m denotes mass
a denotes acceleration
→ F = 1000 × (-3) N
→ F = –3000 N
∴ The force exerted by the car on the wall 3000 N, negative sign denotes that it is acting in the opposite direction.
☆ Answer is in attachment ☆
