A car of mass 1000 kg rests on a horizontal road initially . It is then pushed over 5 m to a speed of 1 m/s before the engine is started . If the average frictional force acting on the car is 500 N,the total work done in moving the car before the driver starts the engine is.
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Answered by
3
Work done = force×displacement
force = 500N
displacement = 5m
work done = 500×5 = 2500J
force = 500N
displacement = 5m
work done = 500×5 = 2500J
Anonymous:
I was also thinking this , but frictional force ka koi role to ni h na ?
hum jo work kar rahe hain, wo frictional force ko overcome karne ke liye hi jaa raha hai
the force applied by us = friction = 500N
Umm...okiee... :)
you still have doubt?
nahh . okie..
okie..!
Answered by
3
Force applied = frictional force, as the acceleration of the car is 0 during 5 meters...
W = Force applied * displacement = 500 N * 5 m = 2, 500 J
W = Force applied * displacement = 500 N * 5 m = 2, 500 J
THANKS SIR
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