Question

A Car of mass 1000kg develops a force of 500N over a distance of 49 m . if initially the car is at rest find the final velocity

1)0 7 m/s ② 20 m/s ③ 14 m/s ③ 10 m/s​

Answer 1

Answer:

7m/s is the answer

Explanation:

hope it helps you

Answer 2

Answer:

7 m / sec.

Explanation:

Given :

Mass of car = 1000 kg

Force = 500 N

We know :

F = m a

a = 500 / 1000

a = 0.5 m / sec² .

Distance is given 49 m

Initial at rest ( u ) = 0 m / sec.

We have to find final velocity :

From Newton's third law :

v² = u² + 2 a s

v² = 0 + 2 × 2 × 49

v² = 2 × 0.5 × 7 × 7

v² = 1 × 7 × 7

v = 7 m / sec.

Hence the final velocity of car is 7 m / sec.