Physics, asked by rbk26060, 5 months ago

A car of mass 1000kg is accelerating at 2m/s Square. If the resistance to the motion is 1000N, What is the force due to engine?​

Answers

Answered by Shs07
22

Answer : 3000 N

Forces acting on the car are,

  • Weight (downward)
  • Normal reaction by the road (upward)
  • Force by engine (Forward)
  • Resistance (backward)

We are supposed to deal with horizontal forces.

Since the car accelerates with 2 m/s^2.

Therefore,

F_{net} = m.a \\ =  > F_{net} = 1000 \times 2 \\  =  > F_{net} =2000 \: newtons

For the car to accelerate at the rate of 2 m/s^2 the Net Force acting on it should be 2000 N.

Hence,

Force  \: by  \: engine + Force \:  of \:  friction = Net  \: Force

Here, Force by friction(resistance) is in opposite direction,

So, f = - 1000 N

Therefore,

F_{engine} + F_{resistance } = 2000 \\  =  > F_{engine} + ( - 1000) = 2000 \\  =  > F_{engine} = 2000 + 1000

 =  > F_{engine} = 3000

Hope this helps.

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