Question

A car of mass 1000kg is moving on a horizontal circle of radius 200m.coefficient of friction between ground and tyres is .2 find the friction force acting on yhe tyres if the car is moving witj speed 30m/s

Answer 1

m = 1000kg
r = 200m
v = 30 m/s
Coefficient of friction(c) = 0.2


Centrifugal force acting on the car = mv^2/r = 1000×30^2/200 = 4500 N


The centripetal force is provided by the friction acting on the wheels.

Maximum friction that can act on the wheels = cmg = 0.2×1000×9.8 = 1960 N

Since the centrifugal force is more than the maximum friction, the friction actin on the car will be maximum.

Hence friction acting on the car is 1960 N.

Answer 2

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m = 1000kg

r = 200m

v = 30 m/s

Coefficient of friction(c) = 0.2

Centrifugal force acting on the car = mv^2/r = 1000×30^2/200 = 4500 N

The centripetal force is provided by the friction acting on the wheels.

Maximum friction that can act on the wheels = cmg = 0.2×1000×9.8 = 1960 N

Since the centrifugal force is more than the maximum friction, the friction actin on the car will be maximum.

Hence friction acting on the car is 1960 N.