Question

a car of mass 1000kg moving with a velocity of 45 km/hr collides a tree and stops in 5s.What will be the force exerted by car on tree.
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Answer 1

Acceleration will be

$\frac{0 - (45 \times \frac{5}{18} )}{5} \\ \frac{0 - 2.5 \times 5}{5} \\ \frac{0 - 12.5}{5} \\ \frac{ - 12.5}{5} \\ - 2.5 \: m {s}^{ - 2}$

Retardation will be 2.5 m/s²

Now,
Force = 1000*2.5
2500 Newtons

Thanks_

Answer 2

Answer:

Force, F = -2500 N

Explanation:

It is given that,

Mass of the car, m = 1000 kg

Initial speed of the car, u = 45 km/hr = 12.5 m/s

It stops, v = 0

Time taken, t = 5 s

We need to find the  force exerted by car on tree. It can be calculated using the formula as follows :

F = ma

$F=m\times \dfrac{v-u}{t}$

$F=1000\times \dfrac{0-12.5}{5}$

F = -2500 N

So, the force exerted by the car on tree is -2500 N. Hence, this is the required solution.