Question

A car of mass 1000kg negotiates a banked curve of radius 90 m on a frictionless road .If the banking angle 45, then find speed of the car.

Answer 1

Answer:

tanθ = v^2/rg

tan45 = v^2/90 x 10

v^2 = 900

v = 30 m/s

Answer 2

The speed of the car is 30 m/s.

Step-by-step explanation:

Given:

Mass of the car $m=1000kg$.

The radius of the curve $r=90m$.

The angle$\theta=45^{o}$

$g=10m/s^{2}$

To find:

Find the speed of the car.

Formula used: $tan\theta=\frac{v^{2} }{rg}$

Solution:

The angle of banking $tan\theta=\frac{v^{2} }{rg}$

$tan45^{o}=\frac{v^{2} }{90\times10}=1$

$V^{2}=900$

$v=\sqrt{900} m/s$

$v=30m/s$

Hence, the speed of the car is $30m/s$.

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