A car of mass 1000kg traveling at speed 32m/s dashed into the rear of a truck of mass 8000kg moving with velocity 4m/s in the same direction. After collision the car bounces with velocity of 8m/s. what is velocity of truck after impact
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Step-by-step explanation:
m1 = 1000 kg
v1 = 32 m/s
m2 = 8000 kg
v2 = 4 m/s.
after collision, v11 = – 8 m/s v21 = 2
momentum is conserved hence m1v1 + m2 v2
= m1 v11 + m2 v21 (1000 × 32) + (8000 × 4)
= (1000 × – 8) + (8000 v21)
∴ 32000 + 32000
= – 8000 + 8000 v21
∴ 64000 = 8000 (v21 – 1)
∴ v21 – 1 = 8 v21
= 9 m/s
hope this helps
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