Question

A car of mass 100kg is moving with a certain velocity. It is brought to rest by the application of brakes, within a distance of 10m when the average resistance being offered to it is 250N.What was the velocity of the motor car?

Answer 1

Answer:

5√2 m/s

Explanation:

m= 100 kg

s= 10 m

f=-250N

initial velocity=?

final velocity=0

acceleration= F/M=-250/100=-2.5m/s2

we have v2-u2= 2as

u2= v2-2as

= 0-2(-2.5)×10 m2/s2

=50 m2/s2

u=√50

u=√25×2

u=5√2m/s