A car of mass 1200 kg initially at rest has been accelerated to speed of 8m/s in 16 meters. Average acceleration of car is ? m/s^2 and force is ? N.
A. 1.5 and 1500
B. 2.5 and 2400
C. 3.5 and 3500
D. 2 and 2400
Data: mass= 2kg, vi=0, vf=8m/s, S=16m, a=?, f=?
Solution:
a= (vf^2 - vi^2)/2S
a=(8^2 - 0) / 2(16)
a= 64/32 =32/16=16/8=4/2=2 m/s^2
F=ma=(1200)(2)=2400 N.
Right answer is D.
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Answers
Answered by
0
Answer:
a=4m/S square
f= 4800n
Explaination:
given:
m=1200kg
v=8m/s
d=16m
t= v/t= 2 sec
a = v-u/t
= 8-0/2
=4
F = ma
= 1200×4
=4800N
hence found
Answered by
3
Answer:
D. 2 and 2400
Hope it helps you ✌️
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