Question

A car of mass 1200 kg is brought to rest from a speed of 60 ms" by a constant breaking force of 6000 N. Calculate the relay
and the time in which the car comes to rest.

Answer it if you know only then........ wrong answer will be reported.....​

Answer 1

Answer:

v = 0m/s

u = 60m/s

F = ma

a = (v-u)/t

F = m(v-u)/t

Now substitute

6000 = 1200a

a = 6000/1200

= 5

Retardation = 5m/s2

a = 5

(v-u)/t = 5

= -60/t = 5

= -12s

Explanation:

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Answer 2

Answer:

A car of mass m=1200kg moving initially at u=90m/s

=90×5/18=25m/s

let the braking force be given as,

f=−3600t [as f various linearly with time]

The braking force causes retardation,which given by :-

a= f/m= −3600t/1200=−3t

as, a=dv/dt=−3t ⇒∫dv=∫−3dt

=v−u=3t²/2

As u=25m/s , we get:-

v= −3t²/2+25

when car comes to halt v=0 so:-

25=3t²/2⇒t= √50/3s

Explanation:

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