A car of mass 1200 kg is moving on the road at the speed of 60 km/h.if the coefficient of the friction is 38 and the normal force is 50 N, then wt is the frictional force acting on the car?
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the normal force due to the moving vehicle
=mg
=1200×10
=12000
friction force
=u N
=u mg
=38×12000
=45600N
I think this is the answer
I hope this helps ( ╹▽╹ )
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