A car of mass 1200 kg is moving on the road at the speed of 60 km/h.if the coefficient of friction is 38 and the normal force is 50N, what is the frictional force acting on the car.
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Given: mass=1200 kg
Speed=16m/s
Coeffi fric(u)=38
Normal reaction=mg downwards=50
To find out:friction
Formula:u×normal reaction
Sol:now the velocity and mass is just given to confuse us and is termed as superfluous data which is of no use as u can see from the formula
Therfore friction=u x mg
=50 x 38
=1900 N
As there is no need of any other information when the normal force is given as friction depends on normal reaction and not the velocity of an object. If y answer didnt match ur options then ull have check it out with ur phy sir
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